This one is working correctly. Remember that splitting a substring
up into words takes place after the substring has been identified in
the source string by using a pattern. Hence in your example:
parse data n first =(n) second
The first pattern is found (=(n)), and the string is split at that
point (position 10). Then the 9 characters thus found are split
into the first word (placed in the variable 'n') and the remainder
(placed in the variable 'first'). So 'n' doesn't get the value 5
until after the pattern has been used.
If you used a pattern to separate off the first word (similar to
the example in NRL on page 129):
parse data n ' ' first =(n) second
then the variable 'n' will get its new value before it is used in the
second pattern. (This wouldn't work if there could be a blank before
the number.)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Mike Cowlishaw, IBM Fellow, IBM UK Laboratories
mailto:
[hidden email] [
http://www2.hursley.ibm.com]
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