Nitpicking #42

[Martin Lafaix]

Is there a more elegant way to test the identity of two Rexx
strings than:

  if (Object string1) == (Object string2) then
    ...

The above works just fine, but I find it ugly, long to type and
not that readable :-)

[In case some are wondering, I'm doing tens of millions of
 comparisons between Rexx strings, and, for space and efficiency,
 they are all resolved through a pool, so that two Rexx strings
 are equal if and only if they are the same object.  Comparing
 10,000,000 times two identical 26-characters Rexx strings takes
 12" here when using Rexx's ==.  One hundred time that (i.e.,
 1,000,000,000) comparisons with the code given above takes less
 that 6".  I _want_ those seconds :-) ]


Martin
--
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Team OS/2
http://www.multimania.com/lafaix

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[Mike Cowlishaw-2]

The sequence

  if (Object string1) == (Object string2) then ...

is the right way to do this.   I've considered adding an 'ultra-strict
compare' (=== and \===) for this, but not entirely convinced it's needed
:-)


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Mike Cowlishaw, IBM Fellow
mailto:[hidden email]  --  http://www2.hursley.ibm.com


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[mcbrides]

>
>
>The sequence
>
>  if (Object string1) == (Object string2) then ...
>
>is the right way to do this.   I've considered adding an 'ultra-strict
>compare' (=== and \===) for this, but not entirely convinced it's needed
>:-)

I'd happily except a more strict compare option. One question, would it behave
faster than the current strict (==) compare?



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[Mike Cowlishaw-2]

Ultra-strict: would mean 'objects must be the same object', rather than
'objects must contain the same characters in same order'.

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Mike Cowlishaw, IBM Fellow
mailto:[hidden email]  --  http://www2.hursley.ibm.com


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